The area (in sq. units) bounded by y = 1 x and y = 1 2 x - 1 between x = 1 and x = 2 is

Step-by-step solution

Required area = ∫ 1 2 1 x - 1 2 x - 1 d x = ln ⁡ x - 1 2 ln ⁡ 2 x - 1 1 2 = ln ⁡ 2 - 1 2 ln ⁡ 3 - ln ⁡ 1 - 1 2 ln ⁡ 1 = ln ⁡ 2 3 sq. units