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NTA Abhyas JEE Main2020MathematicsArea Under CurvesPractice

The area between the curves x = 4 y - y 2 and x = 0 is λ square units, then the value of 3 λ is equal to

Options

  1. A28
  2. B30
  3. C32
  4. D36

Correct answer

C. 32

Step-by-step solution

The required area is (say A ) A = ∫ 0 4 x ⋅ d y = ∫ 0 4 4 y - y 2 d y = 2 y 2 - y 3 3 0 4 = 32 - 64 3 = 32 3 ⇒ 3 λ = 3 2

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