NTA Abhyas JEE Main2020MathematicsArea Under CurvesPractice
The area (in sq. units) bounded between y = 2 x ln x and y = - x from x = e to x = 2 e is
Options
- Ae 2 ln 16
- Be 2 ln 16 e 3
- Ce 3 ln 16
- De 3 ln 16 e 3
Correct answer
B. e 2 ln 16 e 3
Step-by-step solution
As y = 2 x ln ⁡ x > 0 and y = - x < 0   ∀ x ∈ e , 2 e The required area is A = ∫ e 2 e 2 x ln ⁡ x + x d x = ∫ e 2 e d x 2 ln ⁡ x = x 2 ln ⁡ x e 2 e = 4 e 2 ln ⁡ 2 e - e 2 = e 2 ln ⁡ 16 e 3 sq. units