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NTA Abhyas JEE Main2020MathematicsArea Under CurvesPractice

The area (in sq. units) of the region in the first quadrant bounded by y = x 2 , y = 2 x + 3 and the y -axis is

Options

  1. A2 3
  2. B6
  3. C9
  4. D44 3

Correct answer

C. 9

Step-by-step solution

In first quadrant y = x 2 and y = 2 x + 3 meet at x = 3 Hence, the required area = ∫ 0 3 2 x + 3 - x 2 d x = x 2 + 3 x - x 3 3 0 3 = 9 sq. units

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