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NTA Abhyas JEE Main2020MathematicsCirclePractice

The least value of the quadratic polynomial, f x = 2 p 2 + 1 x 2 + 2 4 p 2 - 1 x + 4 2 p 2 + 1 for real values of p and x is

Correct answer

3

Step-by-step solution

y = 2 p 2 x 2 + 4x + 4 + x 2 - 2 x + 1 + 3 y = 2 p 2 x + 2 2 + x - 1 2 + 3 p = 0 , x = 1 y min = 3

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