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NTA Abhyas JEE Main2020MathematicsCirclePractice

Equation of the straight line which meets the circle x 2 + y 2 = 8 at two points where these points are at a distance of 2 units from the point A 2 , 2 is

Options

  1. Ax + y = 2
  2. Bx + y = 3
  3. Cx + y = 1
  4. Dx + y = 0

Correct answer

B. x + y = 3

Step-by-step solution

Equation of circle assuming A 2 , 2 as centre and radius equal to 2 units is x - 2 2 + y - 2 2 = 2 2 … 1 equation of given circle is x 2 + y 2 = 8 … 2 equation 2 – equation 1 gives 4 x + 4 y - 8 = 4 ⇒ x + y = 3 which is the required equation

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