NTA Abhyas JEE Main2020MathematicsCirclePractice
The equation of the chord A B of the circle x 2 + y 2 = 2 passing through the point P 2 ,   2 such that P B P A = 3 is given by
Options
- Ax = 3 y
- Bx = y
- Cy - 2 = 3 x - 2
- DNone of these
Correct answer
B. x = y
Step-by-step solution
We know, P A . P B = P T 2 = 2 2 + 2 2 - 2 = 6 …(1) P B P A = 3 …(2) From (1) and (2), we get, P A = 2   ,     P B = 3 2 ⇒   A B = 2 2 . Now, the diameter of the circle is 2 2 (as the radius is 2 ) Hence, the line passes through the center ⇒ y = x