If 4 x + 3 y - 12 = 0 touches x - p 2 + y - p 2 = p 2 , then the sum of all the possible values of p is

Step-by-step solution

The distance of the centre p , p of the given circle from the line 4 x + 3 y - 12 = 0 is equal to the radius p ⇒ 4 p + 3 p - 12 5 = p ⇒ 7 p - 12 = 5 p or 7 p - 12 = - 5 p ⇒ p = 6 or p = 1 ⇒ sum of all the possible values of ‘ p ’ = 6 + 1 = 7