Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
NTA Abhyas JEE Main2020MathematicsCirclePractice

The equation of the circle which passes through the points A 0,5 and B 6,1 and whose centre lies on the line 12 x + 5 y = 25 is

Options

  1. A3 x 2 + 3 y 2 + 10 x + 6 y + 15 = 0
  2. B3 x 2 + 3 y 2 - 10 x - 6 y - 45 = 0
  3. Cx 2 + y 2 - 6 x - 6 y + 5 = 0
  4. Dx 2 + y 2 - 4 x - 3 y - 10 = 0

Correct answer

B. 3 x 2 + 3 y 2 - 10 x - 6 y - 45 = 0

Step-by-step solution

Centre C of the required circle lies on the perpendicular bisector of the line segment joining 0,5 & 6,1 the midpoint of line segment joining A & B is 3,3 = D Slope of A B is - 2 3 Slope of D C is 3 2 ⇒ equation of D C is 3 x - 2 y - 3 = 0 C is the point of intersection of 3 x - 2 y - 3 = 0 and 12 x + 5 y = 25 ⇒ C = 5 3 , 1 Radius = A C = 25 9 + 16 = 13 3 ⇒ equation of the circle is x - 5 3 2 + y - 1 2 = 13 3 2 ⇒ 3 x 2 + 3 y 2 - 10 x - 6 y - 45 = 0

Practice Circle on Quantrex Academy →

More from Circle

Match each entry in List-I to the correct entry in List-II and choose the correct option. List-I List-II (P) The circle with centre (1, 2) and touching the straight line 3x + 4y = 2026Consider the circle C: x^2+y^2-6x-8y-11=0 . Let a variable chord AB of the circle C subtend a right angle at the origin. If the locus of the foot of the perpendicular drawn from th 2026Let C be a circle having centre in the first quadrant and touching the x -axis at a distance of 3 units from the origin. If the circle C has an intercept of length 6 3 on y -axis, 2026Let the line x - y = 4 intersect the circle C: (x-4)^2 + (y+3)^2 = 9 at the points Q and R . If P( , ) is a point on C such that PQ = PR , then (6 + 8 )^2 is equal to __________. 2026Let the centre of the circle x^2 + y^2 + 2gx + 2fy + 25 = 0 be in the first quadrant and lie on the line 2x - y = 4 . Let the area of an equilateral triangle inscribed in the circl 2026Let P be a moving point on the circle x^2 + y^2 - 6x - 8y + 21 = 0 . Then, the maximum distance of P from the vertex of the parabola x^2 + 6x + y + 13 = 0 is equal to: 2026Suppose that two chords, drawn from the point (1, 2) on the circle x^2 + y^2 + x - 3y = 0 are bisected by the y -axis. If the other ends of these chords are R and S , and the mid p 2026Let a circle pass through the origin and its centre be the point of intersection of two mutually perpendicular lines x + (k-1)y + 3 = 0 and 2x + k^2 y - 4 = 0 . If the line x - y + 2026 Full Circle list All NTA Abhyas JEE Main PYQs