NTA Abhyas JEE Main2020MathematicsCirclePractice
If the chord of contact of the tangents from the point α , β to the circle x 2 + y 2 = r 1 2 is a tangent to the circle x - a 2 + y - b 2 = r 2 2 , then
Options
- Ar 2 2 α 2 + β 2 = r 1 2 - a α - b β 2
- Br 2 2 α 2 + β 2 = r 1 2 + a α - b β 2
- Cr 2 2 α 2 + β 2 = r 1 2 - a α + b β 2
- Dr 2 2 α 2 + β 2 = r 1 2 + a α + b β 2
Correct answer
A. r 2 2 α 2 + β 2 = r 1 2 - a α - b β 2
Step-by-step solution
The equation of the chord of contact of tangents drawn from a point α , β to the circle x 2 + y 2 = r 1 2 is α x + β y = r 1 2 This line touches the circle x - a 2 + y - b 2 = r 2 2 ∴ a α + b β - r 1 2 α 2 + β 2 = r 2 ⇒ r 2 2 α 2 + β 2 = a α + b β - r 1 2 2 ⇒ r 2 2 α 2 + β 2 = r 1 2 - a α - b β 2