NTA Abhyas JEE Main2020MathematicsCirclePractice
If the circles x - 3 2 + y - 4 4 = 16 and x - 7 2 + y - 7 2 = 9 intersect at points A and B , then the area (in sq. units) of the quadrilateral C 1 A C 2 B is equal to (where, C 1 and C 2 are centres of the given circles)
Options
- A6
- B12
- C18
- D24
Correct answer
B. 12
Step-by-step solution
So, area of quadrilateral = 2 area ∆ A C 1 C 2 = 2 1 2 3 4 = 12 square units