NTA Abhyas JEE Main2020MathematicsCirclePractice
The equation of a circle with the origin as the centre and passing through the vertices of an equilateral triangle whose altitude is of length 3 units is
Options
- Ax 2 + y 2 = 9
- Bx 2 + y 2 = 16
- Cx 2 + y 2 = 4
- Dx 2 + y 2 = 1
Correct answer
C. x 2 + y 2 = 4
Step-by-step solution
Circle circumscribes the triangle A B C and has center at 0 , 0 . A D = 3 ∴ O A = 2 3 × 3 = 2 ∴ radius of circle, O A = 2 Thus, equation of circle is x 2 + y 2 = 4