NTA Abhyas JEE Main2020MathematicsCirclePractice
The locus of the centre of the circle which makes equal intercepts on the lines x + y = 1 and x + y = 5 is
Options
- Ax - y = 2
- Bx + y = 6
- Cx + y = 3
- Dx - y = 0
Correct answer
C. x + y = 3
Step-by-step solution
Let center be h , k Since it makes equal intercepts on the two given lines Hence, the center is equidistant from both the lines i.e. h + k - 1 2 = h + k - 5 2 ⇒ h + k = 3