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NTA Abhyas JEE Main2020MathematicsCirclePractice

The equation of incircle of the triangle formed by common tangents to the circles x 2 + y 2 = 4 and x 2 + y 2 - 6 x + 8 = 0 is

Options

  1. Ax 2 + y 2 = 1
  2. Bx 2 + y 2 - 6 x + 8 = 0
  3. Cx 2 + y 2 - 6 x + 9 = 0
  4. Dx 2 - y 2 = 1

Correct answer

B. x 2 + y 2 - 6 x + 8 = 0

Step-by-step solution

Note that circles touch each other externally, hence the smaller circle is incircle of the triangle formed by common tangents.

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