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NTA Abhyas JEE Main2020MathematicsCirclePractice

The equation of the circumcircle of the square formed by the lines x 2 - 8 x + 12 = 0 and y 2 - 14 y + 45 = 0 is

Options

  1. Ax 2 + y 2 - 4 x - 7 y + 57 = 0
  2. Bx 2 + y 2 - 8 x - 14 y + 57 = 0
  3. Cx 2 + y 2 - 8 x - 14 y + 5 = 0
  4. D2 x 2 + y 2 - 8 x - 14 y + 57 = 0

Correct answer

B. x 2 + y 2 - 8 x - 14 y + 57 = 0

Step-by-step solution

The given equation of lines are x - 2 x - 6 = 0 ,   y - 5 y - 9 = 0 i.e. x = 2 ,   x = 6 ,   y = 5 ,   y = 9 Circle with segment joining 2,5 and 6,9 as the diameter is x - 2 x - 6 + y - 5 y - 9 = 0

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