NTA Abhyas JEE Main2020MathematicsCirclePractice
The equation of an ex-circle of a triangle formed by the common tangents to the circle x 2 + y 2 = 4 and x 2 + y 2 - 6 x + 8 = 0 is
Options
- Ax 2 + y 2 = 4
- Bx 2 + y 2 - 6 x + 8 = 0
- Cx 2 + y 2 - 6 x + 9 = 0
- Dx 2 + y 2 = 1
Correct answer
A. x 2 + y 2 = 4
Step-by-step solution
For x 2 + y 2 = 2 2 , the centre is 0 , 0 and radius is 2 units and for x 2 + y 2 - 6 x + 8 = 0 , the centre is 3 , 0 and radius is 1 unit Now, note that the circles touch each other externally, hence the larger circle is an excircle of the triangle formed by the common tangents.