NTA Abhyas JEE Main2020MathematicsContinuity and DifferentiabilityPractice

Let f x = a ; x = π 2 2 x - π 9 + 2 x - π - b ; x > π 2 . If f x is continuous at x = π 2 , then the value of a 2 5 b is

Correct answer

2.40

Step-by-step solution

l i m x → π 2 + f x = f π 2 ⇒ l i m x → π 2 + 2 x - π 9 + 2 x - π - b = a For the denominator to be zero, b = 3 Now, on rationalization l i m x → π 2 + 2 x - π 9 + 2 x - π + 3 9 + 2 x - π - 9 = a ∴ a = 6

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