NTA Abhyas 2020
- Exam
- NTA Abhyas
- Year
- 2020
- Subject
- Mathematics
- Chapter
- Continuity and Differentiability
NTA Abhyas 2020 · Mathematics · Continuity and Differentiability
If f (x) = min \ 9 - x^ 2 , 1 + x^ 2 \ , x ∈ [-3,3], then the...
If the number of point(s) wheref \left(x\right) is non-differentiable is/are![If f (x) = min \ 9 - x^ 2 , 1 + x^ 2 \ , x ∈ [-3,3], then the number of point(s) wheref (x) is non-differentiable is/are](/api/proxy-image?clean=1&url=https%3A%2F%2Ffirebasestorage.googleapis.com%2Fv0%2Fb%2Fquantrexacademy-app.firebasestorage.app%2Fo%2Fquestions%252Ffigs%252Fnta_abhyas%252Fjee_main%252Fimages%252Fde973fde-33e2-423b-b976-9655f956811e.png%3Falt%3Dmedia)
![If f (x) = min \ 9 - x^ 2 , 1 + x^ 2 \ , x ∈ [-3,3], then the number of point(s) wheref (x) is non-differentiable is/are](/api/proxy-image?clean=1&url=https%3A%2F%2Ffirebasestorage.googleapis.com%2Fv0%2Fb%2Fquantrexacademy-app.firebasestorage.app%2Fo%2Fquestions%252Ffigs%252Fnta_abhyas%252Fjee_main%252Fimages%252Fde973fde-33e2-423b-b976-9655f956811e.png%3Falt%3Dmedia)
Options
- A
- B
- C
- D
Correct answer
A.
Step-by-step solution
Using graph of
,
In the figure, we can see the graph of
![If f (x) = min \ 9 - x^ 2 , 1 + x^ 2 \ , x ∈ [-3,3], then the number of point(s) wheref (x) is non-differentiable is/are](/api/proxy-image?url=https%3A%2F%2Ffirebasestorage.googleapis.com%2Fv0%2Fb%2Fquantrexacademy-app.firebasestorage.app%2Fo%2Fquestions%252Ffigs%252Fnta_abhyas%252Fjee_main%252Fimages%252Fde973fde-33e2-423b-b976-9655f956811e.png%3Falt%3Dmedia&clean=1&v=wm2)
Clearly, \left(x\right)x = - 3, {x}_{1}, {x}_{2}, 3 points)
because there are sharp points at and at there are vertical tangents.
,
In the figure, we can see the graph of
![If f (x) = min \ 9 - x^ 2 , 1 + x^ 2 \ , x ∈ [-3,3], then the number of point(s) wheref (x) is non-differentiable is/are](/api/proxy-image?url=https%3A%2F%2Ffirebasestorage.googleapis.com%2Fv0%2Fb%2Fquantrexacademy-app.firebasestorage.app%2Fo%2Fquestions%252Ffigs%252Fnta_abhyas%252Fjee_main%252Fimages%252Fde973fde-33e2-423b-b976-9655f956811e.png%3Falt%3Dmedia&clean=1&v=wm2)
Clearly, \left(x\right)x = - 3, {x}_{1}, {x}_{2}, 3 points)
because there are sharp points at and at there are vertical tangents.