NTA Abhyas JEE Main2020MathematicsContinuity and DifferentiabilityPractice
If f x = e x + x - 1 x + x : x ≠ 0 - 1 : x = 0 (where . denotes the greatest integer function), then
Options
- Af x is continuous at x = 0
- Bl i m x → 0 + f x = - 1
- Cl i m x → 0 - f x = 1
- Dl i m x → 0 + f x = 1
Correct answer
D. l i m x → 0 + f x = 1
Step-by-step solution
f x = e x + x - 1 x + x x ≠ 0 - 1 x = 0 l i m x → 0 - f x = l i m x → 0 - e x + x - 1 x + x = e - 1 - 1 - 1 = e - 1 e l i m x → 0 + f x = l i m x → 0 + e x + x - 1 x + x = l i m x → 0 + e x - 1 x = 1 ∵ LHL ≠ RHL at x = 0 ⇒ f x is discontinuous at x = 0