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If f x = a + c o s - 1 x + b : x ≥ 1 - x : x < 1 is differentiable at x = 1 , then the value of b - a is equal to

Options

  1. A0
  2. B1
  3. C- 1
  4. Dπ 2

Correct answer

D. π 2

Step-by-step solution

Since, f ( x ) is differentiable, it must be continuous at x = 1 &#8756; f 1 - = f 1 + = f 1 - 1 = a + c o s - 1 1 + b ... 1 f ' x = &#8722; 1 1 &#8722; x + b 2 : x &#8805; 1 &#8722; 1 : x &#60; 1 Now, for f x to be differentiable at x = 1 f &#8242; 1 &#8722; = f &#8242; 1 + - 1 1 - 1 + b 2 = - 1 &#8658; 1 - 1 + b 2 = 1 &#8658; b = - 1 ... 2 From equation 1 & 2 - 1 = a + &#960; 2 &#8658; a = - &#960; 2 - 1

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