NTA Abhyas JEE Main2020MathematicsContinuity and DifferentiabilityPractice
Let f x = max x , x 2 x ≤ 3 12 - x 3 < x ≤ 12 . If S is the set of points in the interval - 12 , 12 at which f is not differentiable, then S is
Options
- Aequal to - 3 , 3
- Bequal to - 3 , - 1 , 1 , 3
- Can empty set
- Dequal to - 3 , - 1 , 0 , 1 , 3
Correct answer
D. equal to - 3 , - 1 , 0 , 1 , 3
Step-by-step solution
Here, f x = 12 + x - 12 ≤ x < - 3 x 2 - 3 ≤ x ≤ - 1 x - 1 < x < 1 x 2 1 ≤ x ≤ 3 12 - x 3 < x ≤ 12 Hence, f x is not differentiable at x = - 3 , - 1 , 0 , 1 , 3 ⇒ S = - 3 , - 1 , 0 , 1 , 3