In the balanced chemical reaction IO_ 3 ^ - +a I ^ - +b H^ + → c H _ 2 O+ d I_ 2 a, b, c and d respectively corresponds to

Correct answer: A. 5,6,3,3 aligned & : IO_ 3 ^ - +a I^ - +b H^ + → c H_ 2 O+ d I_ 2 & Step 1: I^ - arrow I_ 2 (oxidation) & IO_ 3 ^ - arrow I_ 2 (reduction) Step 2: 2 IO_ 3 ^ - +12 H^ + arrow I_ 2 +6 H_ 2 O & Step 3: 2 IO_ 3 ^ - +12 H^ + +10 e^ - arrow I_ 2 +6 H_ 2 O & 2 I^ - arrow I_ 2 +2 e^ - & Step 4: 2 IO_ 3 ^ - +12 H^ + +10 e^ - arrow I_ 2 +6 H_ 2 O & [2 I^ - arrow I_ 2 +2 e] ×5 aligned aligned & Step 5: 2 IO_ 3 ^ - +10 I^ - +12 H^ + → 6 I_ 2 +6 H_ 2 O IO_ 3 ^ - +5 I^ - +6 H^ + → 3 I_ 2 +3 H_ 2 O aligned On comparing, a=5, b=6, c=3, d=3 .

AIIMS 2005

Exam: AIIMS
Year: 2005
Subject: Chemistry
Chapter: Redox Reactions

AIIMS 2005 · Chemistry · Redox Reactions

In the balanced chemical reaction IO_ 3 ^ - +a I ^ - +b H^ + → c H...

In the balanced chemical reaction

\mathrm{IO}_{3}^{-}+a

\mathrm{I}

^{-}+b \mathrm{H}^{+} → c \mathrm{H}

}_{2}

\mathrm{O}+

\mathrm{I}_{2}

a, b, c

and

respectively corresponds to

Options

A $5,6,3,3$
B $5,3,6,3$
C $3,5,3,6$
D $5,6,5,5$

Correct answer

A. $5,6,3,3$

Step-by-step solution

\begin{aligned}& : \mathrm{IO}_{3}^{-}+a \mathrm{I}^{-}+b \mathrm{H}^{+} → c \mathrm{H}_{2} \mathrm{O}+ d \mathrm{I}_{2} \\ & \text{ Step }1: \mathrm{I}^{-} \rightarrow \mathrm{I}_{2} \text{ (oxidation) }\\ & \quad \mathrm{IO}_{3}^{-} \rightarrow \mathrm{I}_{2} \text{ (reduction) }\\ \text{ Step }2: 2 \mathrm{IO}_{3}^{-}+12 \mathrm{H}^{+} \rightarrow \mathrm{I}_{2}+6 \mathrm{H}_{2} \mathrm{O}\\ & \text{ Step }3: 2 \mathrm{IO}_{3}^{-}+12 \mathrm{H}^{+}+10 e^{-} \rightarrow \mathrm{I}_{2}+6 \mathrm{H}_{2} \mathrm{O}\\ & \quad 2 \mathrm{I}^{-} \rightarrow \mathrm{I}_{2}+2 e^{-} \\ & \text{Step }4: 2 \mathrm{IO}_{3}^{-}+12 \mathrm{H}^{+}+10 e^{-} \rightarrow \mathrm{I}_{2}+6 \mathrm{H}_{2} \mathrm{O}\\ & \quad\left[2 \mathrm{I}^{-} \rightarrow \mathrm{I}_{2}+2 e\right] \times5 \end{aligned}

\begin{aligned} & \text{ Step }5: 2 \mathrm{IO}_{3}^{-}+10 \mathrm{I}^{-}+12 \mathrm{H}^{+} → 6 \mathrm{I}_{2}+6 \mathrm{H}_{2} \mathrm{O}\\ \mathrm{IO}_{3}^{-}+5 \mathrm{I}^{-}+6 \mathrm{H}^{+} → 3 \mathrm{I}_{2}+3 \mathrm{H}_{2} \mathrm{O} \end{aligned}

On comparing,

a=5, b=6, c=3, d=3

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