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NTA Abhyas JEE Main2020MathematicsDifferentiationPractice

If f x = x + 1 ; x > 1 0 ; x = 1 7 - 3 x ; x < 1 then f ′ 0 equals to

Options

  1. A- 1
  2. B- 2
  3. C- 3
  4. D- 4

Correct answer

C. - 3

Step-by-step solution

As for x < 1 , f x = 7 - 3 x ⇒ f &prime; x = - 3 ⇒ f &prime; 0 = - 3

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