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NTA Abhyas 2020
Exam
NTA Abhyas
Year
2020
Subject
Mathematics
Chapter
Differentiation

NTA Abhyas 2020 · Mathematics · Differentiation

If f(x) = \ cases x + 1; & x > 1 0; & x = 1 7 - 3x; & x < 1 cases )...

If f\left(x\right) = \left\{\begin{cases}x + 1; & x > 1 \\ 0; & x = 1 \\ 7 - 3x; & x < 1\end{cases}\right) then f^{′} \left(0\right) equals to

Options

  1. A−1- 1
  2. B−2- 2
  3. C−3- 3
  4. D−4- 4

Correct answer

C. −3- 3

Step-by-step solution

As for x < 1, f\left(x\right) = 7 - 3x ⇒ f^{&prime;}\left(x\right) = - 3 ⇒ f^{&prime;}\left(0\right) = - 3
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