NTA Abhyas JEE Main2020MathematicsDifferentiationPractice
If u = x 2 + y 2 and x = s + 3 t ,   y = 2 s - t , then d 2 u d s 2 is equal to (where t is a constant)
Options
- A12
- B32
- C36
- D10
Correct answer
D. 10
Step-by-step solution
Given, u = x 2 + y 2 , x = s + 3 t ,   y = 2 s - t Now , d x d s = 1 , d y d s = 2 … ( i ) d 2 x d s 2 = 0 , d 2 y d s 2 = 0 … ( i i ) Now, u = x 2 + y 2 d u d s = 2 x d x d s + 2 y d y d s d 2 u d s 2 = 2 d x d s 2 + 2 x d 2 x d s 2 + 2 d y d s 2 + 2 y d 2 y d s 2 ⇒ d 2 u d s 2 = 2 1 2 + 2 x 0 + 2 2 2 + 2 y 0     ( from   ( i )   and   ( i i ) ) = 2 + 8 = 10