NTA Abhyas JEE Main2020MathematicsDifferentiationPractice
If y = 1 x , then the value of d y 1 + y 4 + d x 1 + x 4 + 3 is equal to
Options
- A0
- B3
- C4
- D- 3
Correct answer
B. 3
Step-by-step solution
y = 1 x ⇒ d y d x = - 1 x 2 ⇒ x 2 d y   +   d x = 0 ⇒ x 2 dy 1 + x 4 + d x 1 + x 4 = 0 ⇒ d y 1 x 4 + 1 + d x 1 + x 4 = 0 ⇒ d y 1 + y 4 + d x 1 + x 4 = 0 ⇒ d y 1 + y 4 + d x 1 + x 4 + 3 = 3