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NTA Abhyas JEE Main2020MathematicsDifferentiationPractice

If x = sec ⁡ t + tan ⁡ t and y = sec ⁡ t - tan ⁡ t , where t is a parameter, then the value of d y d x when x = 1 3 is

Options

  1. A0
  2. B- 3
  3. C3
  4. D1 3

Correct answer

B. - 3

Step-by-step solution

∵ x y = 1 ⇒ y = 1 x d y d x = - 1 x 2 at x = 1 3 , d y d x = - 3

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