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NTA Abhyas JEE Main2020MathematicsDifferentiationPractice

If f x = x – 1 x – 2 x – 3 x – 4 x – 5 , then the value of f ′ 5 is equal to

Options

  1. A0
  2. B120
  3. C24
  4. D5

Correct answer

C. 24

Step-by-step solution

f ′ x = x – 2 x – 3 x – 4 x – 5 + x − 1 x − 3 x − 4 x − 5 + . . . . . . + x - 1 x - 2 x - 3 x - 4 Putting x = 5 , we get, f ′ 5 = 0 + 0 + 0 + 0 + 5 − 1 5 − 2 5 − 3 5 − 4 f ′ 5 = 24

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