NTA Abhyas JEE Main2020MathematicsFunctionsPractice
If f : R → A defined as f x = t a n - 1 4 x 2 + x + 1 is surjective, then A is equal to
Options
- A- π 2 , π 2
- B0 , π 2
- Cπ 3 , π 2
- D0 , π 3
Correct answer
C. π 3 , π 2
Step-by-step solution
∵ x 2 + x + 1= x + 1 2 2 + 3 4 ∴ 4 x 2 + x + 1 ≥ 3 ⇒ 4 x 2 + x + 1 ≥ 3 ∴ Range of f x is π 3 , π 2