NTA Abhyas JEE Main2020MathematicsFunctionsPractice
The domain of the function f x = 1 9 - x 2 + l o g 20 x 3 - 3 x is
Options
- A- 3 , 0 ∪ 3 , ∞
- B- 3 , 0 ∪ 3 , 3
- C- 3 , 0 ∪ 3 , ∞
- D- 3 , 0 ∪ 3 , 3 ∪ 3 , ∞
Correct answer
D. - 3 , 0 ∪ 3 , 3 ∪ 3 , ∞
Step-by-step solution
9 - x 2 ≠ 0 and x 3 - 3 x > 0 x ≠ - 3 , 3 .... ( 1 ) and x x 2 - 3 > 0 ⇒ x x + 3 x - 3 > 0 x ∈ - 3 , 0 ∪ 3 , ∞ …. 2 From 1 ∩ 2 , we get, x ∈ - 3 , 0 ∪ 3 , 3 ∪ 3 , ∞