NTA Abhyas JEE Main2020MathematicsFunctionsPractice
The range of the function f x = 2 3 x 2 - 4 x + 5 is
Options
- A- ∞ , 2 11 3
- B- ∞ , 2 11 3
- C2 11 3 , ∞
- D2 11 3 , ∞
Correct answer
C. 2 11 3 , ∞
Step-by-step solution
f x is defined if 3 x 2 - 4 x + 5 ≥ 0 ⇒ 3 x 2 - 4 3 x + 5 3 ≥ 0 ⇒ x - 2 3 2 + 11 9 ≥ 0 Which is true for all real x ∴ Domain f = - ∞ , ∞ Let, y = 2 3 x 2 - 4 x + 5 ⇒ y 2 4 = 3 x 2 - 4 x + 5 i . e .   3 x 2 - 4 x + 5 - y 2 4 = 0 For x to be real, 16 - 12 5 - y 2 4 ≥ 0 ⇒ y 2 ≥ 11 3 ∴ Range of y = 2 11 3 , ∞ .