NTA Abhyas JEE Main2020MathematicsFunctionsPractice
The domain of the function f x = 4 x 12 - x 9 + x 4 - x + 1 is
Options
- A- ∞ , - 1
- B1 , ∞
- C- 1 , 1
- D- ∞ , ∞
Correct answer
D. - ∞ , ∞
Step-by-step solution
f x is defined for x 12 - x 9 + x 4 - x + 1 > 0 ⇒ x 4 x 8 + 1 - x x 8 + 1 + 1 > 0 ⇒ x 8 + 1 x x 3 - 1 + 1 > 0 If x ≥ 1 or x ≤ - 1 , then the above expression is positive. If - 1 < x ≤ 0 , the above inequality still holds. If 0 < x < 1 , then x 12 - x x 8 + 1 + x 4 + 1 > 0 as x 4 + 1 > x 8 + 1 s o x 4 + 1 > x x 8 + 1 Hence, the domain of f = - ∞ , ∞ .