NTA Abhyas 2020
- Exam
- NTA Abhyas
- Year
- 2020
- Subject
- Mathematics
- Chapter
- Inverse Trigonometric Functions
NTA Abhyas 2020 · Mathematics · Inverse Trigonometric Functions
The value of ( ^ -1 x) is
The value of
Options
- A
- B
- C
- D
Correct answer
C.
Step-by-step solution
Let,&
\dfrac{1}{\sin^{2 } \text{A}} = 1 + x^{2} ⇒ \text\sin\text{A} = 1 / \sqrt{1 + x^{2}}
⇒ \text\sin \left(\cot^{-1 } \text{x}\right) = 1 / \sqrt{1 + x^{2}}
\dfrac{1}{\sin^{2 } \text{A}} = 1 + x^{2} ⇒ \text\sin\text{A} = 1 / \sqrt{1 + x^{2}}
⇒ \text\sin \left(\cot^{-1 } \text{x}\right) = 1 / \sqrt{1 + x^{2}}