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NTA Abhyas JEE Main2020MathematicsInverse Trigonometric FunctionsPractice

The range of the function f x = s i n - 1 x 2 1 + x 2 , x ∈ R is

Options

  1. A- π 2 , π 2
  2. B0 , π 2
  3. C0 , π 2
  4. D- π 2 , π 2

Correct answer

B. 0 , π 2

Step-by-step solution

x 2 1 + x 2 = 1 - 1 1 + x 2 ∈ 0,1 ∴ Range of f x ∈ s i n - 1 0 , s i n - 1 1 ∈ 0 , π 2

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