NTA Abhyas JEE Main2020MathematicsInverse Trigonometric FunctionsPractice
If f x = c o s - 1 x 3 2 - 1 - x - x 2 + x 3 , ∀ 0 ≤ x ≤ 1 , then the minimum value of f x is
Correct answer
0
Step-by-step solution
f x = c o s - 1 x x - 1 - x 1 - x 2 = c o s - 1 x x - 1 - x 2 1 - x 2 = c o s - 1 x + c o s - 1 x At x = 1 , minimum value of f ( x ) = 0