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NTA Abhyas 2020
Exam
NTA Abhyas
Year
2020
Subject
Mathematics
Chapter
Inverse Trigonometric Functions

NTA Abhyas 2020 · Mathematics · Inverse Trigonometric Functions

If f(x) = co s ^ - 1 (x(3)/(2) - 1 - x - x ^ 2 + x ^ 3 ), 0 ≤ x ≤ 1...

If f(x)=cos−1(x32−1−x−x2+x3),∀0≤x≤1f\left(x\right) = co{s}^{- 1}\left(x\dfrac{3}{2} - \sqrt{1 - x - {x}^{2} + {x}^{3}}\right), \forall 0 \le x \le 1, then the minimum value of f(x)f\left(x\right) is

Correct answer

0

Step-by-step solution

f(x)=cos−1{xx−(1−x)(1−x2)}f\left(x\right) = co{s}^{- 1}\left\{x\sqrt{x} - \sqrt{\left(1 - x\right)\left(1 - {x}^{2}\right)}\right\}
=cos−1{xx−1−(x)21−x2}= co{s}^{- 1}\left\{x\sqrt{x} - \sqrt{1 - {\left(\sqrt{x}\right)}^{2}}\sqrt{1 - {x}^{2}}\right\}
=cos−1x+cos−1x= co{s}^{- 1}x + co{s}^{- 1}\sqrt{x}

At x=1x = 1,

minimum value of f(x)=0f ( x ) = 0

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