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NTA Abhyas 2020
Exam
NTA Abhyas
Year
2020
Subject
Mathematics
Chapter
Inverse Trigonometric Functions

NTA Abhyas 2020 · Mathematics · Inverse Trigonometric Functions

For x ∈ (0, (π)/(2)), if cos^ - 1 ((7)/(2)(1 + 2x) + (sin^ 2 x -...

For x∈(0,π2),x \in \left(0, \dfrac{\pi}{2}\right), if cos−1(72(1+cos⁡2x)+(sin2x−48cos2x)sinx)=x−cos⁡−1(kcosx),cos^{- 1}\left(\dfrac{7}{2}\left(1 + \cos 2x\right) + \sqrt{\left(sin^{2}x - 48cos^{2}x\right)}sin x\right)= x - \cos^{-1}\left(kcos x\right),
then the value of kk is equal to

Options

  1. A11
  2. B55
  3. C77
  4. D1414

Correct answer

C. 77

Step-by-step solution

y=cos−1y = cos^{- 1}\left(\dfrac{7}{2} (1+cos⁡2x)+(sin2x−48cos2x)\left(1 + \cos 2x\right) + \sqrt{\left(sin^{2}x - 48cos^{2}x\right)}sin x\right)<br/><br/><br /><br />= cos^{- 1} \left(\left(7cos x\right)\left(cos x\right)++\sqrt{1 - 49\cos^{2}x}\sqrt{1 - \cos^{2}x}\right)<br/><br/><br /><br />= cos^{- 1} \left(cos x\right)−cos−1(7cosx)- cos^{- 1} \left(7cos x\right)

=x−cos−1(7cosx)<br/><br/>Hence,= x - cos^{- 1} \left(7cos x\right)<br /><br />Hence, the value ofk = 7
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