NTA Abhyas JEE Main2020MathematicsInverse Trigonometric FunctionsPractice
The minimum value of x which satisfies the inequality s i n - 1 x ≥ c o s - 1 x is λ , then the value of 2 λ is (use 2 = 1.41 )
Correct answer
1.41
Step-by-step solution
Using the graphs of s i n - 1 x & c o s - 1 x , we can see that s i n - 1 x ≥ c o s - 1 x for x ∈ 1 2 , 1 So, the minimum value of x is λ = 1 2 Hence, 2 λ = 2