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NTA Abhyas 2020
Exam
NTA Abhyas
Year
2020
Subject
Mathematics
Chapter
Inverse Trigonometric Functions

NTA Abhyas 2020 · Mathematics · Inverse Trigonometric Functions

The minimum value of x which satisfies the inequality (si n ^ - 1...

The minimum value of xx which satisfies the inequality ${\left(si{n}^{- 1}x\right)}^{2} \ge {\left(co{s}^{- 1}x\right)}^{2} isThe minimum value of x which satisfies the inequality (si n ^ - 1 x) ^ 2 ≥ (co s ^ - 1 x) ^ 2 is

Options

  1. A12\dfrac{1}{\sqrt{2}}
  2. B12\dfrac{1}{2}
  3. C32\dfrac{\sqrt{3}}{2}
  4. D13\dfrac{1}{\sqrt{3}}

Correct answer

A. 12\dfrac{1}{\sqrt{2}}

Step-by-step solution

The minimum value of x which satisfies the inequality (si n ^ - 1 x) ^ 2 ≥ (co s ^ - 1 x) ^ 2 is
(sin−1x)2−(cos−1x)2≥0{\left(si{n}^{- 1}x\right)}^{2} - {\left(co{s}^{- 1}x\right)}^{2} \ge 0
\left(si{n}^{- 1}x + co{s}^{- 1}x\right)\left(si{n}^{- 1}x - co{s}^{- 1}x\right) \ge 0<br/><br />⇒ si{n}^{- 1}x \ge co{s}^{- 1}x<br/>Clearlyfromgraph<br/><br />Clearly from graph<br />x \in \left[\dfrac{1}{\sqrt{2}}, 1\right]
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