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NTA Abhyas 2020
Exam
NTA Abhyas
Year
2020
Subject
Mathematics
Chapter
Inverse Trigonometric Functions

NTA Abhyas 2020 · Mathematics · Inverse Trigonometric Functions

The domain of the function f (x) = 4 ^ -1 ((1 - |x|)/(2)) is

The domain of the function ff\left(x\right) = 4\sqrt{\cos^{-1} \left(\dfrac{1 - \left|x\right|}{2}\right)} is

Options

  1. A(−∞,−3)∪(3,∞)\left(- \infty, - 3\right) \cup \left(3, \infty\right)
  2. B[−3,3]\left[- 3,3\right]
  3. C(−∞,−3]∪[3,∞)\left(- \infty, - 3\right] \cup \left[3, \infty\right)
  4. Dϕϕ

Correct answer

B. [−3,3]\left[- 3,3\right]

Step-by-step solution

cos⁡−1\cos^{- 1}\left(\dfrac{1 - \left|x\right|}{2}\right) is defined if

−1≤1−∣x∣2≤1- 1 \le \dfrac{1 - \left|x\right|}{2} \le 1
⇒−2≤1−∣x∣≤2⇒−3≤−∣x∣≤1⇒ - 2 \le 1 - \left|x\right| \le 2 ⇒ - 3 \le - \left|x\right| \le 1
⇒−1≤∣x∣≤3⇒ - 1 \le \left|x\right| \le 3
\left|x\right| \ge - 1istrueforallrealvaluesofis true for all real values ofx.<br/>∣x∣≤3⇒−3≤x≤3.<br />\left|x\right| \le 3 ⇒ - 3 \le x \le 3
Also, 4cos⁡−1(1−∣x∣2)4\sqrt{\cos^{- 1} \left(\dfrac{1 - \left|x\right|}{2}\right)} is defined if

cos⁡−1(1−∣x∣2)≥0\cos^{- 1} \left(\dfrac{1 - \left|x\right|}{2}\right) \ge 0
⇒1−∣x∣2≥cos⁡0=1⇒ \dfrac{1 - \left|x\right|}{2} \ge \cos 0 = 1
⇒1−∣x∣≥2⇒ 1 - \left|x\right| \ge 2
⇒∣x∣≤−1⇒ \left|x\right| \le - 1 (not possible)
∴∴ Domain of f(x)=[−3,3]f\left(x\right) = \left[- 3,3\right]

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