NTA Abhyas 2020
- Exam
- NTA Abhyas
- Year
- 2020
- Subject
- Mathematics
- Chapter
- Inverse Trigonometric Functions
NTA Abhyas 2020 · Mathematics · Inverse Trigonometric Functions
The value of 2 ^ -1 (4)/(5) + 2 ^ -1 (5)/(13) + 2 ^ -1 (16)/(65) is...
The value of is equal to
Options
- A
- B
- C
- D
Correct answer
C.
Step-by-step solution
2 \left[\sin^{- 1} \dfrac{16}{65}\right]<br />= 2\sin^{- 1} \left(\dfrac{4}{5}\sqrt{1 - {\left(\dfrac{5}{13}\right)}^{2}} + \dfrac{5}{13}\sqrt{1 - {\left(\dfrac{4}{5}\right)}^{2}}\right) +2\sin^{- 1} \dfrac{16}{65}
= 2 \left[\sin^{- 1} \left(\dfrac{63}{65}\right) + \sin^{- 1} \left(\dfrac{16}{65}\right)\right]
=2\left[\cos^{- 1}\left(\dfrac{16}{65}\right) + \sin^{- 1} \left(\dfrac{16}{65}\right)\right]\left(∵ \sin^{- 1} x = \cos^{- 1}\sqrt{1 - x^{2}}\right)
= 2 \left[\sin^{- 1} \left(\dfrac{63}{65}\right) + \sin^{- 1} \left(\dfrac{16}{65}\right)\right]
=2\left[\cos^{- 1}\left(\dfrac{16}{65}\right) + \sin^{- 1} \left(\dfrac{16}{65}\right)\right]\left(∵ \sin^{- 1} x = \cos^{- 1}\sqrt{1 - x^{2}}\right)