Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
NTA Abhyas JEE Main2020MathematicsSequences and SeriesPractice

0.2 + 0.22 + 0.222 + … upto n terms is equal to

Options

  1. A2 9 - 2 81 1 - 10 - n
  2. Bn 1 9 1 - 10 - n
  3. C2 9 n - 1 9 1 - 10 - n
  4. D2 9

Correct answer

C. 2 9 n - 1 9 1 - 10 - n

Step-by-step solution

0.2 + 0.22 + 0.222 + . . . n terms = 2 0.1 + 0.11 + 0.111 + … n t e r m s = 2 1 10 + 11 100 + 111 1000 + … n t e r m s = 2 9 9 10 + 99 100 + 999 1000 + … n t e r m s = 2 9 1 - 1 10 + 1 - 1 100 + 1 - 1 1000 + … n t e r m s = 2 9 n - 1 10 + 1 100 + 1 1000 + … n = 2 9 n - 1 10 1 - 1 10 n 1 - 1 10 = 2 9 n - 1 10 × 10 9 . 10 n - 1 10 n = 2 9 n - 1 9 1 - 10 - n

Practice Sequences and Series on Quantrex Academy →

More from Sequences and Series

Let = 3+4+8+9+13+14+ upto 40 terms. If ( )^ 1020 is a root of the equation x^2+x-2=0 , (0, 2 ) , then ^2 + 3 ^2 is equal to: 2026The sum 1 + 1 2 (1^2 + 2^2) + 1 3 (1^2 + 2^2 + 3^2) + upto 10 terms is equal to : 2026The value of 1^3 - 2^3 + 3^3 - + 15^3 is: 2026The sum of the first ten terms of an A.P. is 160 and the sum of the first two terms of a G.P. is 8 . If the first term of the A.P. is equal to the common ratio of the G.P. and the 2026For the functions f( ) = ^2 + ^2 , and g( ) = ^2 + ^2 , > > 0 , let _ 0 < < /2 f( ) = _ 0 < < g( ) . If the first term of a G.P. is ( 2 ) , its common ratio is ( 2 ) and the sum of 2026If the sum of the first 10 terms of the series 1 1 + 1^4 4 + 2 1 + 2^4 4 + 3 1 + 3^4 4 + 4 1 + 4^4 4 + is m n , (m, n) = 1 , then m + n is equal to : 2026Let A₁, A₂, A₃, , A₃₉ be 39 arithmetic means between the numbers 59 and 159 . Then the mean of A₂₅, A₂₈, A₃₁ and A₃₆ is equal to : 2026Let the sum of the first n terms of an A.P. be 3n^2 + 5n . Then the sum of squares of the first 10 terms of the A.P. is: 2026 Full Sequences and Series list All NTA Abhyas JEE Main PYQs