NTA Abhyas JEE Main2020MathematicsSequences and SeriesPractice
The sum to the infinite terms of the series 5 3 2 ⋅ 7 2 + 9 7 2 ⋅ 1 1 2 + 13 1 1 2 ⋅ 1 5 2 + . . . . is
Options
- A1 8
- B1 36
- C1 54
- D1 72
Correct answer
D. 1 72
Step-by-step solution
T k = 5 + k - 1 4 3 + k - 1 4 2 7 + k - 1 4 2 = 4 k + 1 4 k - 1 2 4 k + 3 2 = 1 8 1 4 k - 1 2 - 1 4 k + 3 2 S n = T 1 + T 2 + T 3 + . . . . + T n = 1 8 1 3 2 - 1 7 2 + 1 7 2 - 1 1 1 2 + 1 1 1 2 - 1 1 5 2 + . . . . + 1 4 n - 1 2 - 1 4 n + 3 2 = 1 8 1 3 2 - 1 4 n + 3 2 S ∞ = l i m n → ∞ S n = 1 8 1 9 - 0 = 1 72