NTA Abhyas JEE Main2020MathematicsSequences and SeriesPractice
If a < 1 and b < 1 , then the sum of the series a a + b + a 2 a 2 + b 2 + a 3 a 3 + b 3 + … is
Options
- Aa 1 - a + a b 1 - a b
- Ba 2 1 - a 2 + a b 1 - a b
- Cb 1 - b + a 1 - a
- Db 2 1 - b 2 + a b 1 - a b
Correct answer
B. a 2 1 - a 2 + a b 1 - a b
Step-by-step solution
We have, a < 1 ,   b < 1 ∴       a b = a b < 1 Now, a a + b + a 2 a 2 + b 2 + a 3 a 3 + b 3 + …   =       a 2 + a 4 + a 6 + … + a b + a b 2 + a b 3 + … =   a 2 1 - a 2 + a b 1 - a b