NTA Abhyas JEE Main2020MathematicsSequences and SeriesPractice
If a 1 + a 5 + a 10 + a 15 + a 20 + a 24 = 225 , then the sum of the first 24 terms of the arithmetic progression a 1 ,   a 2 ,   a 3 . . . . . is equal to
Options
- A450
- B675
- C900
- D1200
Correct answer
C. 900
Step-by-step solution
S = a 1 + a 2 + a 3 + . . . . + a 23 + a 24 S = 24 2 a 1 + a 24 = 12 a 1 + a 24 Given that, a 1 + a 5 + a 10 + a 15 + a 20 + a 24 = 225 ⇒ a 1 + a 1 + 4 d + a 1 + 9 d + a 24 - 9 d + a 24 - 4 d + a 24 = 225 ⇒ 3 a 1 + a 24 = 225 ⇒ a 1 + a 24 = 75 ⇒ S = 12 a 1 + a 24 = 12 × 75 = 900