NTA Abhyas JEE Main2020MathematicsSequences and SeriesPractice
Sum of the series P = 1 2 1 + 2 + 1 3 2 + 2 3 + 1 4 3 + 3 4 + … + 1 100 99 + 99 100 is
Options
- A1 10
- B3 10
- C9 10
- D1 2
Correct answer
C. 9 10
Step-by-step solution
t r = 1 r + 1 r + r r + 1 = 1 r r + 1 r + 1 + r × r + 1 - r r + 1 - r = r + 1 - r r r + 1 = 1 r - 1 r + 1 P = ∑ r = 1 99 t r = 1 - 1 100 = 9 10