Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
NTA Abhyas JEE Main2020MathematicsSequences and SeriesPractice

For the series S = 1 + 1 1 + 3 1 + 2 2 + 1 1 + 3 + 5 1 + 2 + 3 2 + 1 1 + 3 + 5 + 7 1 + 2 + 3 + 4 2 + . … … , if the sum of the first 10 terms is K , then 4 K 101 is equal to

Correct answer

5

Step-by-step solution

r t h term, T r = 1 + 2 + 3 + . … … + r 2 1 + 3 + 5 + … + 2 r - 1 = r r + 1 2 2 r 2 = r + 1 2 4 = r 2 + 2 r + 1 4 S 10 = K = 1 4 ∑ r = 1 10 r 2 + 2 r + 1 ⇒ 4 K = ∑ r = 1 10 r 2 + 2 ∑ r = 1 10 r + ∑ r = 1 10 1 = 10 × 11 × 21 6 + 2 10 × 11 2 + 10 = 385 + 110 + 10 = 505 4 K 101 = 5

Practice Sequences and Series on Quantrex Academy →

More from Sequences and Series

Let = 3+4+8+9+13+14+ upto 40 terms. If ( )^ 1020 is a root of the equation x^2+x-2=0 , (0, 2 ) , then ^2 + 3 ^2 is equal to: 2026The sum 1 + 1 2 (1^2 + 2^2) + 1 3 (1^2 + 2^2 + 3^2) + upto 10 terms is equal to : 2026The value of 1^3 - 2^3 + 3^3 - + 15^3 is: 2026The sum of the first ten terms of an A.P. is 160 and the sum of the first two terms of a G.P. is 8 . If the first term of the A.P. is equal to the common ratio of the G.P. and the 2026For the functions f( ) = ^2 + ^2 , and g( ) = ^2 + ^2 , > > 0 , let _ 0 < < /2 f( ) = _ 0 < < g( ) . If the first term of a G.P. is ( 2 ) , its common ratio is ( 2 ) and the sum of 2026If the sum of the first 10 terms of the series 1 1 + 1^4 4 + 2 1 + 2^4 4 + 3 1 + 3^4 4 + 4 1 + 4^4 4 + is m n , (m, n) = 1 , then m + n is equal to : 2026Let A₁, A₂, A₃, , A₃₉ be 39 arithmetic means between the numbers 59 and 159 . Then the mean of A₂₅, A₂₈, A₃₁ and A₃₆ is equal to : 2026Let the sum of the first n terms of an A.P. be 3n^2 + 5n . Then the sum of squares of the first 10 terms of the A.P. is: 2026 Full Sequences and Series list All NTA Abhyas JEE Main PYQs