If the mean of a set of observations x _ 1 , x _ 2 ,..... , x _ 10 is 40 , then the mean of x _ 1 + 4, x _ 2 + 8, x _ 3 + 12,.... , x _ 10 + 40 is

Correct answer: B. 62 Mean = ( x _ 1 + 4) + ( x _ 2 + 8) + ( x _ 3 + 12) +... + ( x _ 10 + 40) 10 = x _ 1 + x _ 2 +... + x _ 10 10 + (4(1 + 2 + 3 +... + 10))/(10) = 40 + 22 = 62 &

NTA Abhyas 2020

Exam: NTA Abhyas
Year: 2020
Subject: Mathematics
Chapter: Statistics

NTA Abhyas 2020 · Mathematics · Statistics

If the mean of a set of observations x _ 1 , x _ 2 ,..... , x _ 10...

If the mean of a set of observations

{x}_{1}, {x}_{2},..... , {x}_{10}

40

, then the mean of

{x}_{1} + 4, {x}_{2} + 8, {x}_{3} + 12,.... , {x}_{10} + 40

Options

A $54$
B $62$
C $38$
D $50$

Correct answer

B. $62$

Step-by-step solution

Mean = \dfrac{\left({x}_{1} + 4\right) + \left({x}_{2} + 8\right) + \left({x}_{3} + 12\right) +... + \left({x}_{10} + 40\right)}{10}

<br />

= \dfrac{{x}_{1} + {x}_{2} +... + {x}_{10}}{10} + \dfrac{4\left(1 + 2 + 3 +... + 10\right)}{10}

<br />

= 40 + 22 = 62
&

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