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NTA Abhyas 2020
Exam
NTA Abhyas
Year
2020
Subject
Physics
Chapter
Atomic Physics

NTA Abhyas 2020 · Physics · Atomic Physics

Assuming f & to be the frequency of the electromagnetic wave...

Assuming ff& to be the frequency of the electromagnetic wave corresponding to the first line in Balmer& series, the frequency of the immediate next line is

Options

  1. A0.5f0. 5f
  2. B1.35f1. 35f
  3. C2.05f2. 05f
  4. D2.70f2. 70f

Correct answer

B. 1.35f1. 35f

Step-by-step solution

For Balmer series, nf{n}_{f} =2 and ni{n}_{i}=3,4,5,....

Frequency, of 1st spectral line of Balmer series

f=RZ2c(122−132)<br/><br/>orf=RZ^{2}c \left(\dfrac{1}{{2}^{2}} - \dfrac{1}{{3}^{2}}\right)<br /><br />orf = RZ^{2}c ×536...(i)<br/><br/>Frequency,\times \dfrac{5}{36} ...(i)<br /><br />Frequency, of 2nd spectral line of Balmer series

f’ =RZ^{2}c \left(\dfrac{1}{{2}^{2}} - \dfrac{1}{{4}^{2}}\right)<br/><br/>or<br /><br />orf′ = RZ^{2}c \times \dfrac{3}{16}....(ii)<br/><br/>Formeqs.(i)and(ii),wehave<br/><br/>....(ii)<br /><br />Form eqs. (i) and (ii), we have<br /><br />\dfrac{f}{f′}= \dfrac{20}{27}<br/><br/><br /><br />∴ f^{′} = \dfrac{27}{20}f = 1.35f
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