Find the atomic number for an atom that emits K _ α radiation with wavelength 4λ , if K _ α wavelength emitted by an atom of atomic number Z = 11 is λ .

Correct answer: A. Z = 6 (1)/(λ) ∝ (z-1) ^ 2 ^ ∴ λ _ 1 λ _ 2 = ( z _ 2 - 1) ^ 2 ( z _ 1 - 1) ^ 2 (1)/(4) = ( Z _ 2 - 1 1 1 - 1 ) ^ 2 Solving this, we get, Z _ 2 = 6

NTA Abhyas 2020

Exam: NTA Abhyas
Year: 2020
Subject: Physics
Chapter: Atomic Physics

NTA Abhyas 2020 · Physics · Atomic Physics

Find the atomic number for an atom that emits K _ α radiation with...

Find the atomic number for an atom that emits

{K}_{α}

radiation with wavelength

4\lambda

, if

{K}_{α}

wavelength emitted by an atom of atomic number

Z = 11

\lambda

Options

A $Z = 6$
B $Z = 4$
C $Z = 11$
D $Z = 44$

Correct answer

A. $Z = 6$

Step-by-step solution

\dfrac{1}{\lambda} ∝ {\left(\text{z-1}\right)}^{2}{}^{}

∴ \dfrac{{λ}_{1}}{{λ}_{2}} = \dfrac{{\left({z}_{2} - 1\right)}^{2}}{{\left({z}_{1} - 1\right)}^{2}}

\dfrac{1}{4} = {\left(\dfrac{{Z}_{2} - 1}{1 1 - 1}\right)}^{2}

Solving this, we get,

{Z}_{2} = 6

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