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The potential difference across a Coolidge tube is 20 kV and 10 mA current flows through the voltage supply. Only 0.5% of the energy, carried by electrons striking the target, is converted into X -ray. Then the power carried by X -ray beam (in W ) is

Correct answer

1

Step-by-step solution

P = V I Total power drawn by the tube = P T = V I = 200 W As 0.5% of energy is carried by electrons, the power of X-ray will be 0.5% × P T = 1 W

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