NTA Abhyas JEE Main2020PhysicsAtomic PhysicsPractice
An X -ray tube produces a continuous spectrum of radiation with a cutoff wavelength of 45 × 10 - 3 nm . The maximum energy of a photon in the radiation (in eV ) is [ h = 6.62 × 10 - 34 J s , c = 3 × 10 8 m s - 1 ]
Options
- A27500
- B22500
- C17500
- D12500
Correct answer
A. 27500
Step-by-step solution
E = h c λ = 6 .62 × 10 - 34 × 3 × 10 8 45 × 10 - 12 J = 0 .44 × 10 - 14 1 .6 × 10 - 19 eV = 0 .275 × 10 5 eV = 27500 eV